Open Access Articles- Top Results for Lake Alfred, Florida

Lake Alfred, Florida

Lake Alfred, Florida
Location in Polk County and the state of Florida
Location in Polk County and the state of Florida

Coordinates: 28°5′37″N 81°43′30″W / 28.09361°N 81.72500°W / 28.09361; -81.72500Coordinates: 28°5′37″N 81°43′30″W / 28.09361°N 81.72500°W / 28.09361; -81.72500{{#coordinates:28|5|37|N|81|43|30|W|region:US_type:city |primary |name=

Country United States
State Florida
County Polk
Incorporated 1915[1]
 • Total 8.6 sq mi (22.2 km2)
 • Land 4.9 sq mi (12.7 km2)
 • Water 3.7 sq mi (9.5 km2)
Elevation 174 ft (53 m)
Population (2013)
 • Total 5,183
 • Density 602.7/sq mi (408.1/km2)
Time zone Eastern (EST) (UTC-5)
 • Summer (DST) EDT (UTC-4)
ZIP code 33850
Area code(s) 863
FIPS code 12-37525[2]
GNIS feature ID 0285214[3]

Lake Alfred is a city in Polk County, Florida, United States. The population was approximately 5,183 in 2013.[4] It is part of the LakelandWinter Haven Metropolitan Statistical Area.


The area known as Lake Alfred was founded by snowbirds escaping the cold of Fargo, North Dakota. They at first named the settlement after their hometown, but the Post Office protested after a series of mix ups with the town of Largo.[5] The town then became Chubb and later Bartow Junction because it lay at the junction of a road leading south into the county seat Bartow. Finally, in 1913 it took the name Lake Alfred after Alfred Parslow, an early settler.[6] In 1917, the State of Florida established the first off-campus center for the University of Florida in Lake Alfred, the Citrus Experiment Station to study ways of improving citrus growing.[7] Today this location is known as the UF/IFAS Citrus Research and Education Center.

Geography and climate

Lake Alfred is located at 28°5′37″N 81°43′30″W / 28.09361°N 81.72500°W / 28.09361; -81.72500{{#coordinates:28|5|37|N|81|43|30|W|type:city | |name= }} (28.093664, -81.724998).[8] Lake Alfred is located within the Central Florida Highlands area of the Atlantic coastal plain with a terrain consisting of flatland interspersed with gently rolling hills.[9]

According to the United States Census Bureau, the city has a total area of Script error: No such module "convert".. Script error: No such module "convert". of it is land and Script error: No such module "convert". of it (42.84%) is water.

Lake Alfred is located in the humid subtropical zone (Köppen climate classification: Cfa).[10]


As of the census[2] of 2000, there were 3,890 people, 1,511 households, and 1,103 families residing in the city. The population density was 793.6 inhabitants per square mile (306.5/km²). There were 1,741 housing units at an average density of 355.2 per square mile (137.2/km²). The racial makeup of the city was 78.25% White, 17.25% African American, 0.23% Native American, 0.80% Asian, 1.72% from other races, and 1.75% from two or more races. Hispanic or Latino of any race were 5.89% of the population.

There were 1,511 households out of which 32.0% had children under the age of 18 living with them, 55.0% were married couples living together, 14.7% had a female householder with no husband present, and 27.0% were non-families. 22.1% of all households were made up of individuals and 10.2% had someone living alone who was 65 years of age or older. The average household size was 2.54 and the average family size was 2.98.

In the city the population was spread out with 26.5% under the age of 18, 7.1% from 18 to 24, 27.2% from 25 to 44, 22.1% from 45 to 64, and 17.0% who were 65 years of age or older. The median age was 38 years. For every 100 females there were 87.1 males. For every 100 females age 18 and over, there were 83.9 males.

The median income for a household in the city was $36,809, and the median income for a family was $42,904. Males had a median income of $31,875 versus $20,445 for females. The per capita income for the city was $18,008. About 10.7% of families and 14.0% of the population were below the poverty line, including 24.1% of those under age 18 and 7.4% of those age 65 or over.


The city is served by buses of Winter Haven Area Transit.


The city was established soon after the South Florida Railroad reached the area in 1883.[11] It had a number of early names, including Fargo, Chubb and Bartow Junction. The name Lake Alfred was adopted in 1913, and was taken from the nearest large lake, named for Alfred Parslow, who came to Florida in 1877 and obtained a charter to build the Jacksonville, Tampa and Key West Railroad.[12]



  1. ^ "Guide to Polk, Auburndale". The Ledger. Retrieved 2010-09-25. 
  2. ^ a b "American FactFinder". United States Census Bureau. Retrieved 2008-01-31. 
  3. ^ "US Board on Geographic Names". United States Geological Survey. 2007-10-25. Retrieved 2008-01-31. 
  4. ^ U. S. Census Bureau Quick Facts, Internet website [1], accessed September 11, 2014.
  5. ^ Whitehead, Bill (14 August 1960). "First Polk Settlers Had to Build Towns, Then Name Them". <span />Lakeland Ledger<span />. pp. 7–A. Retrieved 22 April 2015. 
  6. ^ "Names of Polk Cities" (PDF). Polk County Historical Association. March 1978. Retrieved 2010-09-25. 
  7. ^ "CES" (PDF). Polk County Historical Association. December 2003. p. 1. Retrieved 2010-09-25. 
  8. ^ "US Gazetteer files: 2010, 2000, and 1990". United States Census Bureau. 2011-02-12. Retrieved 2011-04-23. 
  9. ^ "Florida's Geological History". University of Florida. Retrieved 2010-10-14. 
  10. ^ "World Map of the Köppen-Geiger climate classification updated". University of Veterinary Medicine Vienna. 2008-11-06. Retrieved 2010-09-10. 
  11. ^ Frisbie, L.K. (1976) Yesterday's Polk County Imperial Publishing Company, Bartow, FL
  12. ^ Morris, A.(1995) Florida Place Names Pineapple Press

External links