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Palmyra, Hunterdon County, New Jersey

Not to be confused with Palmyra, New Jersey in Burlington County.
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Palmyra, New Jersey
Unincorporated community
Palmyra's location in Hunterdon County (Inset: Hunterdon County in New Jersey)
Location within the state of New Jersey

Coordinates: 40°33′41″N 75°0′55″W / 40.56139°N 75.01528°W / 40.56139; -75.01528Coordinates: 40°33′41″N 75°0′55″W / 40.56139°N 75.01528°W / 40.56139; -75.01528{{#coordinates:40|33|41|N|75|0|55|W|region:US-NJ_type:city |primary |name=

}}
Country United States
State New Jersey
County Hunterdon
Township Alexandria
Elevation[1] 463 ft (141 m)
Time zone Eastern (EST) (UTC-5)
 • Summer (DST) EDT (UTC-4)
GNIS feature ID 879105[1]

Palmyra is an unincorporated community located within Alexandria Township, in Hunterdon County, New Jersey, United States.[1][2][3]

References

  1. ^ a b c Feature Detail Report for: Palmyra, Geographic Names Information System. Accessed January 1, 2015.
  2. ^ Locality Search, State of New Jersey. Accessed January 1, 2015.
  3. ^ Areas covering the point (-75.015278,40.561389), MapIt. Accessed January 1, 2015.